Integral with simple fractions: &#x222B;<!-- ∫ --> <mtext>&#xA0;</mtext> </msub>

manierato5h

manierato5h

Answered question

2022-06-08

Integral with simple fractions:   cos x sin x 1 + cos 2 x d x

Answer & Explanation

rioolpijpgp

rioolpijpgp

Beginner2022-06-09Added 19 answers

Using substitution u = sin x we get
  1   u 2 u 2 d u
Hint
Multiply both numerator and denominator by u and then use the substitution 2 u 2 = t 2 . To get
u u 2 2 u 2 d u = 1 t 2 2 d t .
Now you can use partial fractions.

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