Proving that this integral is divergent <msubsup> &#x222B;<!-- ∫ --> <mrow class="MJX

flightwingsd2

flightwingsd2

Answered question

2022-06-09

Proving that this integral is divergent
0 | sin x | x 2

Answer & Explanation

assumintdz

assumintdz

Beginner2022-06-10Added 22 answers

lim x 0 + ( | sin x | x 2 : 1 x ) = 1 0 0 1 d x x  divergent 
0 1 | sin x | x 2  divergent  0 + | sin x | x 2  divergent.

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