I'm trying to compute the (implicit) derivative dy/dx from the function e^(2y)=x^3 If I use ln on both sides I can isolate y and find the derivative: ln(e^(2y))=ln(x^3) 2y=3ln(x) y=3/2 ln(x) y′=3/2x But if I use implicit differentiation I get: d/dx(e^(2y))=d/dx x^3 d/dy(e^(2y))d/dx(y)=3x^2 2e^(2y)⋅y′=3x^2 y′=(3x^2)/(2e^(2y)) I know both methods should give the same result. What am I missing?

Samson Kaufman

Samson Kaufman

Answered question

2022-08-11

I'm trying to compute the (implicit) derivative d y d x from the function
e 2 y = x 3
If I use ln on both sides I can isolate y and find the derivative:
ln ( e 2 y ) = ln ( x 3 )
2 y = 3 ln ( x )
y = 3 2 ln ( x )
y = 3 2 x
But if I use implicit differentiation I get:
d d x ( e 2 y ) = d d x x 3
d d y ( e 2 y ) d d x ( y ) = 3 x 2
2 e 2 y y = 3 x 2
y = 3 x 2 2 e 2 y
I know both methods should give the same result. What am I missing?

Answer & Explanation

Tristian Clayton

Tristian Clayton

Beginner2022-08-12Added 12 answers

Substitute e 2 y by x 3 in the last line.

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