It was observed that 30 of the 100 randomly selected students smoked. Find the confidence interval estimate of 95\% confidence level for \pi ratio of smokers in the population.(0.45<p<0.78)=0.95P(0.11<p<0.28)=0.95

UkusakazaL

UkusakazaL

Answered question

2021-08-06

It was observed that 30 of the 100 randomly selected students smoked. Find the confidence interval estimate of 95% confidence level for π ratio of smokers in the population.
a) P(0.45<p<0.78)=0.95
b) P(0.11<p<0.28)=0.95
c) P(0.51<p<0.78)=0.95
d) P(0.21<p<0.59)=0.95
e) P(0.21<p<0.39)=0.95

Answer & Explanation

geduiwelh

geduiwelh

Beginner2021-08-09Added 1 answers

The 95% CI is given by
CI=p±z0.05pqn
CI=0.3±1.960.3×0.7100
CI=[0.21, 0.39]
Option (e) is correct.
P(0.21<p<0.39)=0.95

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