necessaryh

2021-02-21

We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 192 had kids. Based on this, plot a $99\mathrm{\%}$ confidence interval for the proportion of adult residents who are parents in a given county.

Express your answer in the form of three inequalities. Provide your responses in decimal fractions up to three places $<p<$ Express the same answer using a point estimate and a margin of error. Provide your responses as decimals, to three places.

$p=\pm$

ottcomn

Skilled2021-02-22Added 97 answers

Step 1

Given that the sample size

Let p denotes the proportion of adult residents who are parents in the country.

Thus, the value of p is given by

From the standard normal table, the Z value at

Substitute the known values in the formula

Step 2

The confidence interval is given by

Here, we have

Hence, the confidence interval in tri-inequality form is

The confidence interval suing point estimate 0.32 and margin of error

Jeffrey Jordon

Expert2021-10-27Added 2605 answers

Answer is given below (on video)

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