Yaritza Estrada
2022-04-12
lildeutsch11xq2j
Beginner2022-04-13Added 13 answers
For the given data, the chi-square test for association is appropriate.
Null Hypothesis:
The televised offense type does not vary by age group of the offender.
Alternative Hypothesis:
The televised offense type vary by age group of the offender.
Procedure for calculating chi-square test statistic using MegaStat:
1. Go to MegaStat > Chi-square/Crosstab > Contingency table.
2. Select the input range of the data as “$A$1:$D$4”.
3. In output options, Select expected values, Chi-square and (O-E)^2/E.
4. Click OK
From the MegaStat output, the chi-square test statistic is 11.36 which is given below:
From the output,
Chi-square is 11.36.
Degree of freedom is 4.
The critical value is 9.488 using the Excel formula '=CHISQ.INV.RT(0.05,4).
Decision rule:
If p-value , then reject the null hypothesis. Otherwise, do not reject the null hypothesis.
Here, p-value is 0.0228, which is less than the level of significance (0.05). Thus, reject the null hypothesis. Thus, the televised offense type varies by age group of the offender.
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