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sibuzwaW

Answered question

2021-10-11

Derivatives involving other trigonometric functions Find the derivative of the following functions.

y = \sec x \tan x

Answer & Explanation

joshyoung05M

Skilled2021-10-12Added 97 answers

Step 1
Given function:

y = \sec x \tan x

Differentiate the above function w.r.t "x"

y^{'} = \frac{d}{d x} \sec x \tan x

Step 2
Apply the product rule

\frac{d}{d x} (m n) = m \frac{d}{d x} (n) + n \frac{d}{d x} (m)

So, we have

y^{'} = \sec x \frac{d}{d x} (\tan x) + \tan x \frac{d}{d x} (\sec x)

y^{'} = \sec x (\sec^{2} x) + \tan x (\sec x \tan x)

y^{'} = \sec^{3} x + \sec x \tan^{2} x

Jeffrey Jordon

Expert2022-11-14Added 2605 answers

Answer is given below (on video)

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