Find the derivatives of the functions defined as follows. y=\ln|\sin x^{2}|ZS

Ayaana Buck

Ayaana Buck

Answered question

2021-10-16

Find the derivatives of the functions defined as follows. y=lnsinx2

Answer & Explanation

cheekabooy

cheekabooy

Skilled2021-10-17Added 83 answers

Step 1
Given function is y=lnsinx2
Step 2
The derivative is given by
y=1sin(x)2×xsin(2x2)sin(x)2
=xsin(2x2)sin2(x2)

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