Find the first and second derivatives of the given function. f(x)=5x^{3}-6x^{2}+6

Krzychau1

Krzychau1

Answered question

2021-12-16

Find the first and second derivatives of the given function.
f(x)=5x36x2+6

Answer & Explanation

Kayla Kline

Kayla Kline

Beginner2021-12-17Added 37 answers

Step 1
The given function is f(x)=5x36x2+6.
The derivative of xn is given by: d dx (xn)=nxn1
therefore the constant's derivative is zero, that is d dx (c)=0.
Step 2
To determine the given function's first derivative f(x)=5x36x2+6, differentiate this function with respect to x.
f(x)=5x36x2+6
f(x)=d dx (6x36x2+6) (since, d dx f(x)=f(x))
f(x)=d dx (5x3)+d dx (6x2)+d dx (6)
f(x)=5d dx (x3)6d dx (x2)+d dx (6)
f(x)=5(3x(31))6(2x(21))+0
f(x)=15x212x
Thus, first derivative of the given function is f(x)=15x212x.
Step 3
By contrasting the first derivative, the second derivative of the given function can be found f(x)=15x212x with respect to x.
f (x)=d dx (15x212x) (since, d2 dx 2f(x)=f (x))
 

chumants6g

chumants6g

Beginner2021-12-18Added 33 answers

d2dx2(5x36x2+6)
ddx(5x36x2+6)=15x212x
=ddx(15x212x)
ddx(15x212x)=30x12
=30x-12

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