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pettingyg0

pettingyg0

Answered question

2022-05-02

Suppose that f , g : R R are functions such that
| f ( x ) f ( y ) | | g ( x ) g ( y ) | | x y |
for any x , y R. If g is differentiable with bounded derivative on all R, show that f is constant.

I know I am meant to be using MVT for this question, I attempted to use g ( x ) as the function because we know it is differentiable (condition required for MVT):
g ( b ) g ( a ) b a = g ( c )
| g ( b ) g ( a ) | = | g ( c ) | b a |
I am lost, not sure where to start the question.

Answer & Explanation

Olive Guzman

Olive Guzman

Beginner2022-05-03Added 16 answers

If the derivative of g is bounded as | g ( c ) | M for all c, then
| f ( x ) f ( y ) x y | | g ( x ) g ( y ) | | x y | M | x y |
for any x , y, where the last inequality is from your application of the mean value theorem. Can you take it from here?

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