How do I solve for a and b in the following equation: <munder> <mo movablelimits="true" f

Leah Pope

Leah Pope

Answered question

2022-06-15

How do I solve for a and b in the following equation:
lim x 0 ( sin ( a x ) + b 2 tan ( b x ) ) = 3
I need to find a value for a and b that is a Real Number. How would I go about doing this? Can Mathmatica help solve this equation?

Answer & Explanation

Sydnee Villegas

Sydnee Villegas

Beginner2022-06-16Added 22 answers

Clearly we must have b 0 otherwise denominator of the function (whose limit is given in the question) will be zero. Now we are given that
lim x 0 sin ( a x ) + b 2 tan ( b x ) = 3
Clearly we can see that
lim x 0 sin ( a x ) + b 2 = lim x 0 sin ( a x ) + b 2 tan ( b x ) tan ( b x ) = 3 0 = 0
or 0+b−2=0 so that b=2. Next note that if a=0 then we have the numerator sin ( a x ) = 0 identically and hence the limit will not be 3. Therefore a 0
We now have
lim x 0 sin ( a x ) tan ( b x ) = lim x 0 sin ( a x ) a x a b b x tan ( b x ) = 1 a b 1 = a 2
Thus a / 2 = 3 and hence a=6. We thus have a=6,b=2.
It is important to show that both a,b are non-zero in order to get the correct answer.

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