Gauss's law for magnetism is stated as followed with the beautiful closed surface double integral : ∯ S ⁡ B ⋅ d A = 0As I understand, the idea is to say that if we sum (continuous sum since integral) all the scalar products between the vector field B (i.e., magnetic field) and surface elements dA defined by their surface normals, we get 0?

Question

Gauss&#039;s law for magnetism is stated as followed with the beautiful closed surface double integral :                              ∯                                      S        ⁡      B    ⋅  d      A    =  0As I understand, the idea is to say that if we sum (continuous sum since integral) all the scalar products between the vector field B (i.e., magnetic field) and surface elements dA defined by their surface normals, we get 0?

Calvin Oneill · Accepted Answer

A double integral in this context means you are integrating over a surface. The integral here is a double integral because a surface is parametrized by two parameters.I think your confusion lies in the notation. A surface integral is sometimes denoted with two integral symbols, but not always. So the integral in the definition of magnetic flux is no different from the integral that appears in Gauss&#039; law for magnetism, which in fact says that the magnetic flux through any closed surface is zero.

Gauss's law for magnetism is stated as followed with the beautiful closed surface double integral :

Answered question

Answer & Explanation

New Questions in Electromagnetism