What determines the dominant pressure-flow relationship for a gas across a flow restriction? If on

Azzalictpdv

Azzalictpdv

Answered question

2022-05-08

What determines the dominant pressure-flow relationship for a gas across a flow restriction?
If one measures the pressure drop across any gas flow restriction you can generally fit the relationship to
Δ P = K 2 Q 2 + K 1 Q
where Δ P is the pressure drop and Q is the volumetric flow
and what I've observed is that if the restriction is orifice-like, K 2 >> K 1 and if the restriction is somewhat more of a complex, tortuous path, K 1 >> K 2 and K 2 tends towards zero.
I get that the Bernoulli equation will dominate when velocities are large and so the square relationship component. But what's determining the K 1 component behavior? Is this due to viscosity effrects becoming dominant? Does the Pouiselle relationship become dominant?

Answer & Explanation

Darion Sexton

Darion Sexton

Beginner2022-05-09Added 14 answers

Solutions that depend upon Δ P Q 2 are related to the normal aerodynamic drag, which just depends upon the ram pressure, ρ   U 2 / 2, a drag coefficient, C d , and the cross-sectional area affected, A, or:
(1) F d = 1 2   ρ   U 2   C d   A
Solutions that depend upon Δ P Q are dominated by Stokes drag, where the drag force is given by:
(2) F s = 6   π   η   r   U
where η is the dynamic viscosity, r is an effective radius or scale-size of the object, and U is the bulk flow velocity relative to the object.
"I get that the Bernoulli equation will dominate when velocities are large and so the square relationship component. But what's determining the K 1 component behavior? Is this due to viscosity effrects becoming dominant? Does the Pouiselle relationship become dominant?"
Yes, it's an effective viscous effect. When the restriction or obstacle are a single shape and flow is relatively steady, laminar, then Equation 1 above dominates. If the flow path has multiple turns or the fluid is highly viscous or the flow is turbulent, then Equation 2 above dominates.
Stokes drag (Equation 2) arises from the strain tensor in the Navier-Stokes equations while the aerodynamic drag (Equation 1) arises from an approximation for the pressure tensor from Bernoulli's equation.
The separation between the two is approximated by the Reynolds number given by:
(3) R e = ρ   U   L η
where ρ is the mass density of the fluid and L is the characteristic scale size. Turbulent flow onsets for high R e, but the onset depends on whether the fluid flows around an obstacle (e.g., R e > 10 5 ) or through a pipe (e.g., R e > 10 3 ).
There simple limits/examples to consider when Equations 1 and 2 dominate. If you try to drag a stick/rod through a thick, viscous fluid like honey then obviously Equation 2 is the relevant drag force. If you drag the same stick/rod through the air as fast as your arm can move, then Equation 1 will dominate.
If you have a fluid that falls in between, then both equations can play significant roles. For instance, air is generally not tremendously viscous but if you force it through a small pipe with multiple bends at high enough speeds, it can behave like a viscous fluid. Unfortunately, the Reynolds number is not an exact parameter, in that it does not state that at the value R e = X then the flow is exactly laminar.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Fluid Mechanics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?