A race car starts from rest on a circular track of radius 400m. The car's speed increases at the constant rate of 0.500m/s^2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, determine the speed of the car ?

Emery Hill

Emery Hill

Answered question

2023-02-28

A race car starts from rest on a circular track of radius 400m. The car's speed increases at the constant rate of 0.500 m / s 2 . At the point where the magnitudes of the centripetal and tangential accelerations are equal, determine the speed of the car ?

Answer & Explanation

Valentino Sloan

Valentino Sloan

Beginner2023-03-01Added 3 answers

Centripetal acceleration a c the following is stated
a c = R ω 2 = v 2 R
where v is linear velocity of the object, ω is its angular velocity and R is the radius of the circle in which object moves.
Tangential acceleration a t is given to be = 0.500   m s - 2
Comparing the size of two and putting in a value R we obtain
v 2 400 = 0.500
v = 0.500 × 400 = 200 = 14.142   m s - 1

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