A bicycle wheel has an initial angular velocity of 1.50 rad/s. (a) If its angular acceleration is constant and equal to&nbsp;0.200rads2, what is its angular velocit at t=2.50 s? (b) Through what angle has the wheel turned between t = 0 and t = 2.50 s?

a) In the given moment, by using equation 9.7 we can get solution, note that the initial speed exists: ωz=ω0z+αzt ωz=1.5rads+0.200rads2⋅2.5 ωz=1.5rads+0.5rads ωz=2rads b) in order to find throught what angel has the wheel turrned well

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High School
Physics
Force, Motion and Energy
Acceleration Due to Gravity

Jessica Scott

Answered question

2021-11-17

A bicycle wheel has an initial angular velocity of 1.50 rad/s. (a) If its angular acceleration is constant and equal to $0.200 r a \frac{d}{s^{2}}$ , what is its angular velocit at t=2.50 s? (b) Through what angle has the wheel turned between t = 0 and t = 2.50 s?

Answer & Explanation

James Kilian

Beginner2021-11-18Added 20 answers

a) In the given moment, by using equation 9.7 we can get solution, note that the initial speed exists:

ω_{z} = ω_{0 z} + α_{z} t

ω_{z} = 1.5 \frac{r a d}{s} + 0.200 \frac{r a d}{s^{2}} \cdot 2.5

ω_{z} = 1.5 \frac{r a d}{s} + 0.5 \frac{r a d}{s}

ω_{z} = 2 \frac{r a d}{s}

b) in order to find throught what angel has the wheel turrned well

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