In an experiment, an object is released from rest near and above Earth's surface. A student must det
uto2rimxrs50
Answered question
2022-05-19
Answer & Explanation
agentbangsterfhes2
Beginner2022-05-20Added 15 answers
The gravitational force of the earth tries to pull an object from the surface of the earth. The direction of this force will be directed towards the centre of the earth. From Newton’s second law any force acting on the object will cause the change in its momentum. If an object is released from rest, the initial velocity if the object will be zero. From the kinematic equations of motion putting the initial velocity as zero
Here, v is the final velocity, s is the distance travelled, g is the acceleration due to the earth’s gravity and t is the time interval.
Step 2
To determine the magnitude of the gravitational force, the acceleration is found. Then the mass time the acceleration gives the gravitational force, The direction of the force is the same as the direction of acceleration since the mass is a scalar quantity.
Taking the velocity and time data or the displacement and time data or the velocity and displacement data will help to find the magnitude of the gravitational force. The direction of the force can be found from the values of velocity at different times since the increase in velocity gives positive acceleration and decrease in velocity gives negative acceleration.
To find the change in momentum of the object, the velocity and time date or the displacement and time data will sufficient since the acceleration is constant.
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