Proof of a formula relating launch velocity of projectile to times of ascent and descent I came across this formula in my textbook stating that when a body is projected vertically upwards and the time corresponding to height H while ascending and descending are t_1 and t_2 respectively, when the velocity of projection is (g(t_1+t_2))/(2) where g is acceleration due to gravity. Can anyone please help me in deriving this formula? I know that in case of vertical motion upwards the initial velocity will be gt1. But I don't know how to proceed further. Please help.

Ayanna Goodman

Ayanna Goodman

Answered question

2022-11-23

Proof of a formula relating launch velocity of projectile to times of ascent and descent
I came across this formula in my textbook stating that when a body is projected vertically upwards and the time corresponding to height H while ascending and descending are t 1 and t 2 respectively, when the velocity of projection is g ( t 1 + t 2 ) 2 where g is acceleration due to gravity.
Can anyone please help me in deriving this formula? I know that in case of vertical motion upwards the initial velocity will be gt1. But I don't know how to proceed further. Please help.

Answer & Explanation

Maffei2el

Maffei2el

Beginner2022-11-24Added 20 answers

The height h ( t ) of the body as a function of time is
h ( t ) = 1 2 g t 2 + v t
with v the initial speed. At t 1 and t 2 , the body will be at the same height. It means that
h ( t 1 ) = h ( t 2 )
h ( t 1 ) = h ( t 2 )
or, equivalently
1 2 g t 1 2 + v t 1 = 1 2 g t 2 2 + v t 2 v ( t 1 t 2 ) = 1 2 g ( t 1 2 t 2 2 ) v = g ( t 1 2 t 2 2 ) 2 ( t 1 t 2 ) = g ( t 1 + t 2 ) 2
Aliyah Thompson

Aliyah Thompson

Beginner2022-11-25Added 3 answers

In other way :
Average Velocity between two points at the different height: V ( a v ) = V 1 + V 2 2 = g t 1 + g t 2 2 = g ( t 1 + t 2 ) 2

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