An inverted cone has a height of 15 mm and a radius of 16mm. The volum

f480forever2rz

f480forever2rz

Answered question

2021-11-29

An inverted cone has a height of 15 mm and a radius of 16mm. The volume of the inverted cone is decreasing a rate of 534 cubic mm per second, with the height begin held constant. What is the rate of change of the radius, in mm per second, when the radius is 6 mm?
Round your answer to the nearest hundreth. (Do not include any units in your answer
Remember that the volume of a cone is =V=13πr2h

Answer & Explanation

Tamara Donohue

Tamara Donohue

Beginner2021-11-30Added 11 answers

Step 1
The volume of a cone is=V=13πr2h
The volume of the inverted cone is decreasing at a rate of 534 cubic mm per second, with the height begin held constant.
=dVdt=13/πh.dr2dt as h is held constant and hence =dhdt=0
Step 2
Find the formula for the rate of change of the volume, in mm per second.
=dVdt=13πhddt(r2)
=13πh(2r)ddt(r)
=23πrhddt(r)
Step 3
To find the rate of changt of the radius, in mm per second, when the radius is 6 mm.
Here =dVdt=534 cubic mm per second, =h=15mm and =r=6mm.
=drdt=23πrhddt(r)
=⇒drdt=32πrhdVdt(r)
=32π×6×15×534
=2.8329

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