The point M is the internal point of the ABC equilateral triangle. Find the angle BMC if |MA|^2=|MB|^2+|MC|^2.

sarahkobearab4

sarahkobearab4

Answered question

2022-08-10

The point M is the internal point of the ABC equilateral triangle. Find the B M C if | M A | 2 = | M B | 2 + | M C | 2 .

Answer & Explanation

Brennan Parks

Brennan Parks

Beginner2022-08-11Added 14 answers

Step 1
Use coordinate geometry. Note that | M A | 2 = | M B | 2 + | M C | 2 is symmetrical in B and C. This means M is located symmetrically with respect to B and C. Let the coordinates of A be ( 0 , 3 a ), B be (-a, 0) and C be (a,0). Since M has to be symmetrical, let the coordinates for M be (0,y).
Step 2
Now, | M A | 2 = | M B | 2 + | M C | 2
y 2 + 2 3 a y a 2 = 0
y = ( 2 3 ) a
Note that you'll get two values of y but it can't be negative
Now since you've M, you can get the angle BMC to be equal to 150 degrees.
orkesruim40

orkesruim40

Beginner2022-08-12Added 3 answers

Step 1
Rotate C around B for 60 and let N be a picture of M under this rotation. What can you say for triangles BMN and AMN?

Step 2
Triangle BMC must be equilateral and since A N 2 + M N 2 = C M 2 + B M 2 = A M 2 we see that triangle ANM is rectangular with 90 at N

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