Let triangle ABC be a triangle and let O be its circumcentre. Let D and M be points on BC such that AD is perpendicular to BC and AM bisects the angle at A. Prove that AM bisects the angle OAD.

Paulkenyo

Paulkenyo

Open question

2022-08-22

Geometry question about bisecting angles
Let A B C be a triangle and let O be its circumcentre. Let D and M be points on BC such that AD is perpendicular to BC and AM bisects the angle at A. Prove that AM bisects the O A D.
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Answer & Explanation

Willow Avery

Willow Avery

Beginner2022-08-23Added 11 answers

Explanation:
Direct angle chasing works. Let the angles of the triangle be α , β , γ.
What is B A O?
Hint: Consider Isosceles triangle BAO. What is A O B?
What is D A C?
Hint: Consider right triangle DAC. What is A C D?
Hence, show that O A M = 90 γ α 2 = M A D.
Colton Gregory

Colton Gregory

Beginner2022-08-24Added 4 answers

Step 1

First we consider B A O, here, B O A = 2. C, since The center angle is twice the circumference angle and B A O = A B O = 1 2 ( 180 ° B O A ) = 1 2 ( 180 ° 2. C ) = 90 ° C
Step 2
Now we consider the A C D, here D A C = 90 ° C
So, B A O = D A C B A M + M A O = M A D + C A M M A O = M A D , since B A M = C A M as AM bisects the A.

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