Find the volume of the intersection of the ellipsoid x^2/a^2+y^2/b^2+z^2/c^2 leq 1 and Ax+By+Cz leq D.

rialsv

rialsv

Answered question

2022-09-28

Volume of a truncated ellipsoid
My objective is to find the volume of the intersection of the ellipsoid
x 2 a 2 + y 2 b 2 + z 2 c 2 1
and A x + B y + C z D
where a , b , c , A , B , C , D R . I have done several attempts but it seems like I have to consider a lot of different cases. My approach is to give a parametrization of the intersection and then finding the volume through solving an integral. However, I can't seem to find a good enough parametrization.

Answer & Explanation

Emmalee Reilly

Emmalee Reilly

Beginner2022-09-29Added 6 answers

Step 1
Define the "step function" θ ( x ) = { 1 ( x > 0 ) ; 0 ( x 0 ) }.
So the volume you want is V = θ ( 1 ( x 2 a 2 + y 2 b 2 + z 2 c 2 ) ) θ ( D ( A x + B y + C z ) ) d x d y d z
Change variables to X = x / a, Y = y / b, Z = z / c (w.l.o.g. a , b , c > 0). Then
V = a b c θ ( 1 ( X 2 + Y 2 + Z 2 ) ) θ ( D ( A a X + B b Y + C c Z ) ) d X d Y d Z
Step 2
Now this is the abc times the volume of a unit sphere cut by a plane. The rest which is cut off the sphere is called a spherical cap. So you need the distance d from the plane to the origin. This can be computed at the locus where the plane D ( A a X + B b Y + C c Z ) meets the plane's normal vector ( X , Y , Z ) = d ( A a , B b , C c ) / ( A a ) 2 + ( B b ) 2 + ( C c ) 2 .
So you get d = D / ( A a ) 2 + ( B b ) 2 + ( C c ) 2 .

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