Solve the following problems applying the Binomial distribuction: What is the probability of obtaining at most twice the number 4, in a 10 throw of a 6-sided die? In the case of the die. We want the probability of obtaining exactly 2 threes in 4 throws.

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Solve the following problems applying the Binomial distribuction:   What is the probability of obtaining at most twice the number 4, in a 10 throw of a 6-sided die?   In the case of the die. We want the probability of obtaining exactly 2 threes in 4 throws.

Alara Mccarthy · Accepted Answer

Step 1- Writing given data Given that Binomial probability distribution. We know that By binomial probability distribution P(X=x)=nCxxPxx(1−P)(n−x) Probability of rolling any number in a die (P)=16 Probability of not rolling given number (1−P)=56 Step 2 - Calculation What is the probability of obtaining at most twice the number 4, in a 10 throw of a 6-sided die? =P(x≤2) Here, n=10; at most twice the number 4.; P=16 P(x≤2)=P(x=2)+P(x=1)+P(x=0) P(x≤2)=10C2x(16)2x(56)(10−2)+10C1x(16)1x(56)(10−1)+10C0x(16)0x(56)(10−0) P(x≤2)=45x(16)2x(56)(8)+10x(16)1x(56)(9)+1x1x(56)(10) P(x≤2)=0.29071+0.32301+0.16150 P(x≤2)=0.77522 The probability of obtaining at most twice the number 4, in a 10 throw of a 6-sided die is 0.77522 In the case of the die. We want the probability of obtaining exactly 2 threes in 4 throws. Here, n=4;x=2;P=16 P(exactly 2 threes)=P(x=2) P(x=2)=4C2x(16)2x(56)(4−2) P(x=2)=6x(16)2x(56)(2) P(x=2)=0.11574 The probability of obtaining exactly 2 threes in 4 throws is 0.11574

Solve the following problems applying the Binomial distribuction: What is the

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