The risk of hepatoma among alcoholics without cirrhosis of the

vestirme4

vestirme4

Answered question

2021-09-16

The risk of hepatoma among alcoholics without cirrhosis of the liver is 24%. Suppose we observe 7 alcoholics without cirrhosis. What is the probability that exactly one of these 7 people have a hepatoma?

Answer & Explanation

Cristiano Sears

Cristiano Sears

Skilled2021-09-17Added 96 answers

Step 1 
We are given, 
Hepatoma is 24% more likely to develop in alcoholics without liver cirrhosis.
That is, p=0.24 
And n=7 
We must determine the probability that each of these seven individuals has a hepatoma.
That is P(x=1)= …………. ? 
Step 2 
Using binomial probability distribution, 
P(X=x)=nCxpx(1p)nx 
Where nCx=n!x!(nx)! 
When we enter values into the formula above, we get
P(X=1)=7C1(0.24)1(10.24)71 
P(X=1)=0.3237 
Step 3 
Therefore, probability that exactly one of these 7 people have a hepatoma =0.3237

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