Amy, Jean, Keith, Tom, Susan, and Dave have all been

Frauffshiesiaf6s

Frauffshiesiaf6s

Answered question

2022-02-11

Amy, Jean, Keith, Tom, Susan, and Dave have all been invited to a birthday party. They arrive randomly and each person arrives at a different time. In how many ways can they arrive?

Answer & Explanation

Bordadwayjpf

Bordadwayjpf

Beginner2022-02-12Added 17 answers

Completely random =720 ways, First and Last set =24 ways, Probability of First and Last happening =130
We have several people arriving to a birthday party in a random order but all at different times. In how many ways can they arrive?
This is a Permutation question - we care about the order in which they arrive. The general equation for Permutations is:
Pn,k=n!(nk)!, where n is the population we can pick from and k is the number of choices were

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