Probability Defective Items Binomial Distribution. Suppose that a large lot with 10000 manufactured items has 30 percent defective items and 70 percent nondefective. You choose a subset of 10 items to test. (a) What is the probability that at most 1 of the 10 test items is defective? (b) Approximate the previous answer using the binomial distribution.

reinzogoq

reinzogoq

Answered question

2022-09-09

Probability Defective Items Binomial Distribution
Suppose that a large lot with 10000 manufactured items has 30 percent defective items and 70 percent nondefective. You choose a subset of 10 items to test. (a) What is the probability that at most 1 of the 10 test items is defective? (b) Approximate the previous answer using the binomial distribution.
I am getting for (a) that P ( at most 1 def item ) = 0.7 10 + ( 10 1 ) 0.3 1 0.7 9
I do not understand what is meant by (b), since the answer for (a) already uses binomial distribution?

Answer & Explanation

SlowlFeet45

SlowlFeet45

Beginner2022-09-10Added 11 answers

Explanation:
The 10 items are not chosen independently since they are chosen without replacement. If it were with replacement, with a tiny chance that the same item might be chosen more than once, then the binomial distribution would be exact rather than a very close approximation. As it is, part (a) must use a hypergeometric distribution. The answer you've written for part (a) is in fact a correct answer to part (b).
Lina Neal

Lina Neal

Beginner2022-09-11Added 1 answers

Step 1
The binomial distribution is only an approximation
More explicitly
Step 2
P ( at most 1 defective  ) = P (  no defective item ) + P ( 1 defective item ) = 7000 10000 6999 9999 6991 9991 + 10 3000 10000 7000 9999 6999 9998 6992 9991

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