In a survey of the number of trips abroad during one year was conduced

Monincbh

Monincbh

Answered question

2021-12-04

In a survey of the number of trips abroad during one year was conduced among 1090 families. The survey reveals the following data:
Number of trips0123456Frequency180110140150200160150
Which of the probabilities bellow (rounded to 2 decimal places) best represent the probability that a family makes 3 trips or less during one
a. 0.47
b. 0.40
c. 0.61
d. 0.53
e. 0.39

Answer & Explanation

Maked1954

Maked1954

Beginner2021-12-05Added 17 answers

Step 1
Given,
A survey of the number of trips abroad during one year was conducted among 1090 families.
Number of trips0123456Frequency180110140150200160150
Step 2
The probability that a family makes 3 trips or less during one year is:
P(X3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)
=180+110+140+1501090
=5801090
=0.5321
=0.53 (rounded to 2 decimals)
Answer is option D

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