The problem is to find the slopes and y-intercepts of the following lines:1) x = − 2and2) y = − 1.I know that for the y-intercept we should set x equal to zero and solve for y. For example, the y intercept for y = 2 x + 3 is ( 0 , 3 ) and slope is 2. For the first equation, which is a line parallel to the y-axis and never crosses it, I think the y-intercept is undefined (or maybe zero) and also the slope is the same.But for the second equation, the y-intercept is − 1 (because it crosses y at − 1 point for all values of x). But I think that the slope is undefined. I think this because if we compare y = − 1 to y = m x + b (where m is the slope), then we can't determine a simple slope.

Question

The problem is to find the slopes and   y-intercepts of the following lines:1)   x  =  −  2and2)   y  =  −  1.I know that for the   y-intercept we should set   x equal to zero and solve for   y. For example, the y intercept for   y  =  2  x  +  3 is   (  0  ,  3  ) and slope is   2. For the first equation, which is a line parallel to the y-axis and never crosses it, I think the y-intercept is undefined (or maybe zero) and also the slope is the same.But for the second equation, the y-intercept is   −  1 (because it crosses   y at   −  1 point for all values of   x). But I think that the slope is undefined. I think this because if we compare   y  =  −  1 to   y  =  m  x  +  b (where   m is the slope), then we can&#039;t determine a simple slope.

sepolturamo · Accepted Answer

For the first one   x  =  −  2 the slope is infinite and there is no   y-intercept. For the second one   y  =  −  1 the slope is   0 and the   y-intercept is   (  0  ,  −  1  ).

hoperetauyk · Accepted Answer

y  =  −  1 can be written   y  =  0  ⋅  x  −  1. So the slope for 2) is 0. The rest of your reasoning seems on track.

The problem is to find the slopes and y -intercepts of the following lines: 1) x = &

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