How do I find the 2 slopes at which this parametric function crosses itself? x ( t )

shmilybaby4i

shmilybaby4i

Answered question

2022-06-12

How do I find the 2 slopes at which this parametric function crosses itself?
x ( t ) = 2 sin ( 2 t ) y ( t ) = 8 sin ( t )

Answer & Explanation

Elianna Douglas

Elianna Douglas

Beginner2022-06-13Added 23 answers

Step 1
There’s no need to abandon parametric form:
d y d x = d y / d t d x / d t = 8 cos t 4 cos 2 t = 2 cos t cos 2 t .
Now just find (in terms of t) where it crosses itself.
migongoniwt

migongoniwt

Beginner2022-06-14Added 4 answers

Step 1
Let x i = 2 sin 2 t i and y i = 8 sin t i , ,
to find the points where the curve crosses it self, we need x i = x j and y i = y j for some i j
So, sin t i = sin t j > ( 1 ) and sin 2 t i = sin 2 t j > ( 2 )
Step 2
1) gives t i = n π + ( 1 ) n t j
2) gives, 2 t i = m π + ( 1 ) m 2 t j where m,n are integers.
If n = 2 q , t i = 2 q π + t j > ( 3 )
If n = 2 q + 1 , t i + t j = ( 2 q + 1 ) π > ( 4 )
If m = 2 r , 2 t i = 2 r π + 2 t j t i = r π + t j > ( 5 )
If m = 2 r + 1 , 2 t i = ( 2 r + 1 ) π 2 t j t i + t j = ( 2 r + 1 ) π 2 > ( 6 )
We can only combine, (3) and (5), so that t i = 2 s π + t j

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