A positron under goes a displacement r=2i-3j+6k ending with the positron vectors r=3j-4k in meters.what was the positron initial positron vectors?

singinscottnud

singinscottnud

Answered question

2023-01-03

A positron under goes a displacement r=2i-3j+6k ending with the positron vectors r=3j-4k in meters.what was the positron initial positron vectors?

Answer & Explanation

Karli Daniel

Karli Daniel

Beginner2023-01-04Added 8 answers

Displacement = final position - initial position
Let,the positron's displacement is given by S and its initial and final positions are expressed as R1 and R2 respectively.
So, S=R2R1
So, R1=R2S
Using the values that are provided,
R1=3j^4k^2i^+3j^6k^
So, R1=2i^+6j^10k^
The initial position vector was as shown.

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