Consider the following. z = x2 + y2, x = 5s + 6t, y = s + t Find ∂z ∂s and ∂z ∂t

Answered question

2021-11-03

Consider the following.

z = x2 + y2,   x = 5s + 6t,   y = s + t

Find 

z
s

 and 

z
t

 by using the chain rule. (Enter your answers in terms of s and t.)

z
s

=

52s+62t

 

z
t

=

62s+74t

 

Find 

z
s

 and 

z
t

 by first substituting the expressions for x and y to write z as a function of s and t. (Enter your answers in terms of s and t.)

z
s

=

 

 

z
t

=

 

Do your answers for 

z
s

 agree?

YesNo    

Do your answers for 

z
t

 agree?

YesNo    

Answer & Explanation

Don Sumner

Don Sumner

Skilled2021-12-21Added 184 answers

z=x2+y2, x=5s+6t, y=s+t

zs=zxxs+zyys
=(2x)(5)+(2y)1
=10x+2y
=10(56+6t)+2(s+t)
=50s+60t+2s+2t
zs=52s+62t
zt=zxxt+zyyt
=2x(6)+2y1=12x+2y
=12(5s+6t)+2(s+t)
=60s+72t+2s+2t
zt=62s+74t
Again - z=(5s+2t)2+(s+t)2
z=(25s2+4t2+20st+s2+t2+2st)
=26s2+5t2+22st
zs=52s+22t
zt=10t+22s
zs Agree - No
zt Agree - No

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