A car heading north collides at an intersection with a truckheading east. If they lock together and travel at 28 m/s at 15∘ north of east just after the collision,how fast was the car initially traveling? Assume that the two vehicles have the same mass. a. 7 m/s b. 28 m/s c. 14 m/s d. 11 m/s

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A car heading north collides at an intersection with a truckheading east. If they lock together and travel at 28 m/s at 15∘ north of east just after the collision,how fast was the car initially traveling? Assume that the two vehicles have the same mass.  a. 7 m/s  b. 28 m/s  c. 14 m/s  d. 11 m/s

Aamina Herring · Accepted Answer

momentum = mv, where m is the mass and v is the velocity (momentum before)y=(momentum after)y 0+mv=2m⋅28sin⁡15 v = 14.49 m/s =14 m/s to 2 sig fig)

Jeffrey Jordon · Accepted Answer

m⋅Vcar+m⋅Vtruck=2m⋅Vcombined  Vcar upwards+Vtruch eastwards=2(28sin⁡46 upwards+28cos⁡46 eastwadds)  equating upwards nad eastwrads componnts  Vcar=2⋅28⋅sin⁡46=40m/s  d)

A car heading north collides at an intersection with a truckheading east. If they lock together and travel at 28 m/s at 15^\circ north of east just after the collision,how fast was the car initially traveling? Assume that the two vehicles have the same mass. a. 7 m/s b. 28 m/s c. 14 m/s d. 11 m/s

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