In an industrial cooling process, water is circulated through a system. If the water is pumped with a speed of 0.45 m/s under a pressure of 400 torr from the first floor through a 6.0-cm diameter pipe, what will be the pressure on the next floor 4.0 m above in a pipe with a diameter of 2.0 cm?

Cem Hayes

Cem Hayes

Answered question

2021-02-18

In an industrial cooling process, water is circulated through a system. If the water is pumped with a speed of 0.45 m/s under a pressure of 400 torr from the first floor through a 6.0-cm diameter pipe, what will be the pressure on the next floor 4.0 m above in a pipe with a diameter of 2.0 cm?

Answer & Explanation

broliY

broliY

Skilled2021-02-20Added 97 answers

In an industrial cooling process, water is circulated through a system.
If the water is pumped with a speed of(v1=0.45ms)
under a pressure of (P1 = 400 torr) from the first floor througha(D1 = 6.0cm) diameter pipe,
Let 'P2' be the pressure on the next floor ( h = 4.0 m ) above in a pipe with adiameter of (D2 = 2.0 cm)
Density of water = 1000kgm3
From the equation of continuity we have
The rate is A1v1=A2v2
Or, v2=A1v1A2
Or, v2=(D1D2)2v1
Apply; Bernoulli's Theorem
P1+(12)v12+0=P2+(12)v22+hg
Put the above given values in the above expression , to get'P2'

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?