 Carla Murphy

2021-12-16

A 2.0 kg , 20-cm-diameter turntable rotates at 130 rpm on frictionless bearings. Two 510 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.
What is the turntables MoxboasteBots5h

Put the values of the question in writing.

Moment of inertia of 2 kf rotating block.
$I=\frac{1}{2}M{R}^{2}$
Block with a 510g moment of inertia.
${I}^{\prime }=\frac{1}{2}m{r}^{2}$
Determine the 510 g block's angular moment with respect to the 2 kg block's rotating center.
${I}^{\prime }{\omega }^{\prime }=\left(1+2m{r}^{2}\right){\omega }^{\prime }$
Calculate a turntable's angular velocity.
No external torque was generated in the situation discussed above, keeping the angular moment constant.
$I\omega ={I}^{\prime }{\omega }^{\prime }$
$I\omega =\left(I+2m{r}^{2}\right){\omega }^{\prime }$
$\frac{m{R}^{2}}{2}×\omega =\left(I+2m{r}^{2}\right)×{\omega }^{\prime }$
$\frac{2×{0.1}^{2}}{2}×130=\left(\frac{2×{0.1}^{2}}{2}+2×0.510×{0.1}^{2}\right)×{\omega }^{\prime }$

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