David Lewis

2021-12-16

A projectile is fired horizontally from a gun that is 45.0 m above flat ground, emerging from the gun with a speed of 250 $\frac{m}{s}$ .

a) How long does the projectile remain in the air?

b) At what horizontal distance from the firing point does it strike the ground?

c) What is the magnitude of the vertical component of its velocity as it strikes the ground?

a) How long does the projectile remain in the air?

b) At what horizontal distance from the firing point does it strike the ground?

c) What is the magnitude of the vertical component of its velocity as it strikes the ground?

Wendy Boykin

Beginner2021-12-17Added 35 answers

Givens:

Part a:

To find the time it stays in in the air we use this equation

Where we set our coordinates so that the bullet starts at vertical position

Therefore

Part b:

To find the horizontal distance from the firing point at which it strikes the ground we use the equation

Where we use the time t we obtained previously and we choose our coordinates so that the particle starts at position

Part c:

Here we need to know the magnitude of

To find the velocity

mauricio0815sh

Beginner2021-12-18Added 34 answers

I make gravitational acceleration to be positive, because as it hits the ground, the bullet is gaining speed; not losing.

I make the value of

Then here's where I'm having conflicting numbers, when | calculate the horizontal distance.

22+64

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