Talamancoeb

2021-12-19

Calculate the frequency of each of the following wavelengths of electromagnetic radiation.

A) 632.8 nm (wavelength of red light from a helium-neon laser) Express your answer using three significant figures.

B) 503 nm (wavelength of maximum solar radiation) Express your answer using three significant figures.

C) 0.0520 nm (a wavelength used in medical X rays) Express your answer using three significant figures.

A) 632.8 nm (wavelength of red light from a helium-neon laser) Express your answer using three significant figures.

B) 503 nm (wavelength of maximum solar radiation) Express your answer using three significant figures.

C) 0.0520 nm (a wavelength used in medical X rays) Express your answer using three significant figures.

Cassandra Ramirez

Beginner2021-12-20Added 30 answers

Step 1

Given: We have to calculate the frequency of each of the following wave length of electromagnetic radiation.

A) Wave length$\left(\lambda \right)=632.8nm=632.8\times {10}^{-9}m$ .

Velocity$\left(c\right)=3\times {10}^{8}\frac{m}{s}$

Frequency$\left(\nu \right)=?$

Now,$C=\lambda \nu$

$\Rightarrow \nu =\frac{c}{\lambda}=\frac{3\times {10}^{8}}{632.8\times {10}^{-9}}=4.74\times {10}^{14}Hz$ .

Hence, the frequency is$4.74\times {10}^{14}Hz$

B) wave length$\left(\lambda \right)=503nm=503\times {10}^{-9}m$

velocity$\left(c\right)=3\times {10}^{8}\frac{m}{s}$

Frequency$\left(\nu \right)=?$

Now,$\nu =\frac{C}{\lambda}=\frac{3\times {10}^{8}}{503\times {10}^{-9}}=5.96\times {10}^{14}Hz$

Hence, the frequency is$5.96\times {10}^{14}Hz$

c) wave length$\left(\lambda \right)=0.052nm=0.052\times {10}^{-9}m$

velocity$\left(c\right)=3\times {10}^{8}\frac{m}{s}$

Frequency$\left(\nu \right)=?$

Now,$\nu =\frac{c}{\lambda}=\frac{3\times {10}^{8}}{0.052\times {10}^{-9}}=5.77\times {10}^{18}Hz$

Hence, the frequency is$5.77\times {10}^{18}Hz$

Given: We have to calculate the frequency of each of the following wave length of electromagnetic radiation.

A) Wave length

Velocity

Frequency

Now,

Hence, the frequency is

B) wave length

velocity

Frequency

Now,

Hence, the frequency is

c) wave length

velocity

Frequency

Now,

Hence, the frequency is

Jenny Sheppard

Beginner2021-12-21Added 35 answers

b) We know energy of photon is given by:

$E=h\nu =\frac{hc}{\lambda}$

where,$h=\text{planles constant}$

$c=\text{speed of light}$

$\lambda =\text{wave length}$

$\nu =\text{frequency}$

$h=6.626\times {10}^{-34}Js$

$c=3\times {10}^{8}ms$ [on $2.998\times {10}^{8}\frac{m}{s}$ ]

$\lambda =503nm=5.03\times {10}^{-7}m$

Putting the values

$E=\frac{6.626\times {10}^{-34}\times 3\times {10}^{8}}{5.03\times {10}^{-7}}J$

$E=\frac{19.878\times {10}^{-19}}{5.03}$

$E=3.95\times {10}^{-19}J$

where,

Putting the values

nick1337

Expert2023-06-13Added 777 answers

Don Sumner

Skilled2023-06-13Added 184 answers

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