Maria Huey

2021-12-20

The atmospheric pressures at the top and the bottom of a building are read b a barometer to be 96.0 and 98.0 kPa. If the density of air is $1.0k\frac{g}{{m}^{3}}$ , the height of the building is (a) 17 m (b) 20 m (c) 170 m (d) 204 m (e) 252 m

Jordan Mitchell

Beginner2021-12-21Added 31 answers

Given:

${P}_{\mathrm{\top}}=96kPa$

${P}_{\mathrm{\perp}\to m}=98kPa$

$\rho =1k\frac{g}{{m}^{3}}$

Solution: We can quickly demonstrate that.

$\mathrm{\u25b3}P={\rho}_{a}g\mathrm{\u25b3}h=1\times 9.81\times \mathrm{\u25b3}h=2\times {10}^{3}Pa\Rightarrow \mathrm{\u25b3}h=\frac{2000}{9.81}=203.874=\approx 204m$

$\mathrm{\u25b3}h=204m$

Ronnie Schechter

Beginner2021-12-22Added 27 answers

Answer:

203.9 m

Step-by-step explanation:

Pressure at top of building

Pressure at bottom of building

difference in pressure

22+64

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