 John Stewart

2021-12-31

$2.0×{10}^{13}$ electrons flow through a transistor in 1.0 ms. What is the current through the transistor? Elaine Verrett

Step 1
The following units that we have are a number of electrons N, and time that they are flowing through a transistor t:
$N=2.0\cdot {10}^{13}$
$t=1.0ms=0.001s$
Step 2
The difinition of current is what is the total rate of flow of charge past a region in a given time. The definition for electric current is:
1) $I=\frac{Q}{t}=\frac{qN}{t}$
where Q is electric charge and q is elemental charge: $q=1.6\cdot {10}^{-19}C$
Total current will be:
Step 3
$I=\frac{1.6\cdot {10}^{-19}\cdot \frac{2}{0}\cdot {10}^{13}}{0.001}$
$=0.0032A$
$=3.2\cdot {10}^{-3}mA$ Fasaniu

Step 1
$I=\frac{\mathrm{\Delta }Q}{\mathrm{\Delta }t}=\frac{\left(nA{v}_{d}\mathrm{\Delta }t\right)q}{\mathrm{\Delta }t}$
The number of charge carriers (electrons) in a volume element is:
${N}_{e}=nA\mathrm{\Delta }x=nA{v}_{d}\mathrm{\Delta }$
Substitute into current equation and solve for current:
$I=\frac{{N}_{e}q}{\mathrm{\Delta }t}$
$=\frac{\left(2.0×{10}^{13}electrons\right)\left(1.60×{10}^{-19}C\right)}{1.0×{10}^{-3}s}$
$3.2×{10}^{-3}$
$A=3.2mA$ Vasquez

Step 1
The magnitude of the charge of one electron is
$q=1.6×{10}^{-19}C$
Therefore, if we have a total of
$N=2.0×{10}^{13}$ electrons, their total charge would be
$Q={N}_{q}=\left(2.0×{10}^{13}\right)\left(1.6×{10}^{-19}C\right)=3.2×{10}^{-6}C$
The current in the transistor is given by
$I=\frac{Q}{t}$
where Q is the total charge of the electrons flowing through it
$t=1.0ms=0.001s$ is the time taken
Substituting into the equation, we find
$I=\frac{3.2×{10}^{-6}C}{0.001s}=0.0032A$

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