2.0×1013 electrons flow through a transistor in 1.0 ms. What is the current through the transistor?

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Elaine Verrett · Accepted Answer

Step 1  The following units that we have are a number of electrons N, and time that they are flowing through a transistor t:  N=2.0⋅1013  t=1.0ms=0.001s  Step 2  The difinition of current is what is the total rate of flow of charge past a region in a given time. The definition for electric current is:  1) I=Qt=qNt  where Q is electric charge and q is elemental charge: q=1.6⋅10−19C  Total current will be:  Step 3  I=1.6⋅10−19⋅20⋅10130.001  =0.0032A  =3.2⋅10−3mA

Fasaniu · Accepted Answer

Step 1 Start with the definition of current: I=ΔQΔt=(nAvdΔt)qΔt The number of charge carriers (electrons) in a volume element is: Ne=nAΔx=nAvdΔ Substitute into current equation and solve for current: I=NeqΔt =(2.0×1013electrons)(1.60×10−19C)1.0×10−3s 3.2×10−3 A=3.2mA

Vasquez · Accepted Answer

Step 1 The magnitude of the charge of one electron is q=1.6×10−19C Therefore, if we have a total of N=2.0×1013 electrons, their total charge would be Q=Nq=(2.0×1013)(1.6×10−19C)=3.2×10−6C The current in the transistor is given by I=Qt where Q is the total charge of the electrons flowing through it t=1.0ms=0.001s is the time taken Substituting into the equation, we find I=3.2×10−6C0.001s=0.0032A

2.0\times10^{13} electrons flow through a transistor in 1.0 ms. What is th

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