fertilizeki

2021-12-30

Two light bulbs have constant resistances of 400 Ω and 800 Ω. If the two light bulbs are connected in series across a 120 V line, find the power dissipated in each bulb

Given:
The resistance across first bulb is ${R}_{1}=400\Omega$
The resistance across second bulb is ${R}_{2}=800\Omega$
The voltage across the builbs is
The formula to calculate the power dissipated in first bulb is,
${P}_{1}=\frac{{V}^{2}}{{R}_{1}}$
Here, ${P}_{1}$ is the power dissipated in first bulb, V is the voltage and ${R}_{1}$ is the resistance across first bulb.
Substitute the khown values in the formula to calculate the power dissipated in first bulb.

The formula to calculate the power dissipated in second bulb is,
${P}_{2}=\frac{{V}^{2}}{{R}_{2}}$
Here, ${P}_{2}$ is the power dissipated in first bulb and ${R}_{2}$ is the resistance across second bulb.
Substitute the known values in the formula to calculate the power dissipated in second bulb.

Thus, the power dissipated in first bulb is  and the power dissipated in second bulb is

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