ajedrezlaproa6j

2022-01-05

A flute player hears four beats per second when she compares her note to a 523 Hz tuning fork (the note C). She can match the frequency of the tuning fork by pulling out the tuning joint to lengthen her flute slightly. What was her initial frequency?

nghodlokl

Beginner2022-01-06Added 33 answers

The beat frequency of two waves is:

${f}_{beat}=|{f}_{1}-{f}_{2}|$

By rewriting this equation we get (higher frequency, so we use the plus sign):

${f}_{2}={f}_{1}+{f}_{beat}=523+4=527Hz$

When the length of the flute is increased, its wavelength also increases thereby its frequency decreases. In order to be equal to the reference frequency (523 Hz), the frequency of the flute must be greater than the reference frequency. So we use the plug sign

By rewriting this equation we get (higher frequency, so we use the plus sign):

When the length of the flute is increased, its wavelength also increases thereby its frequency decreases. In order to be equal to the reference frequency (523 Hz), the frequency of the flute must be greater than the reference frequency. So we use the plug sign

Jonathan Burroughs

Beginner2022-01-07Added 37 answers

Answer:

Initial Frequency$=527Hertz$

Explanation:

Given

Frequency of beat$=4Hertz$

Frequency of Fork$=523Hertz$

Let$Fb=$ Frequency of beat

$Ff=$ Frequency of Fork

The wave length and the length of the flute are directly proportional.

So, when the wavelength gets increased, the length of the flute is also increased.

But it is not so for the frequency.

When the wavelength and the length of the flute are increased, the frequency gets reduced.

For the flute player frequency to equate the frequency of the turning fork, the frequency of the flute must be greater than the frequency of the fork.

So, Frequency$=4+523=527Hertz$

Initial Frequency

Explanation:

Given

Frequency of beat

Frequency of Fork

Let

The wave length and the length of the flute are directly proportional.

So, when the wavelength gets increased, the length of the flute is also increased.

But it is not so for the frequency.

When the wavelength and the length of the flute are increased, the frequency gets reduced.

For the flute player frequency to equate the frequency of the turning fork, the frequency of the flute must be greater than the frequency of the fork.

So, Frequency

karton

Expert2022-01-11Added 613 answers

Answer:

527 Hz

Solution:

As per the question:

Beat frequency of the player,

Frequency of the tuning fork,

Now, the initial frequency can be calculated as:

when,

when,

But we know that as the length of the flute increases the frequency decreases

Hence, the initial frequency must be 527Hz.

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