A cylindrical specimen of steel having an original

Answered question

2022-01-11

A cylindrical specimen of steel having an original diameter of 12.8 mm is tensile tested to fracture and found to have engineering fracture strength σf of 460 MPa. If its cross-sectional diameter at fracture is 10.7 mm, the true stress at fracture will be.

Answer & Explanation

nick1337

nick1337

Expert2022-02-07Added 777 answers

True stress at fracture,

True stress = engineering stress × (1+ true strain) i.e.

σt=σ0(1+e)

Or,

σt=σf×AiAf

Calculation:

Given: di= 12.8 mm, d0 = 10.7 mm, σf = 460 MPa

Now

σt=460×(12.810.7)2

σt=658.28 MPa

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