Total resistance, 1R=IV IV=1Rm+1Rf IV=(AxpfL)+(A(1−x)pmL) x=(((IlpVA))−1)((pfpm−pf) X=[(0.0016×0.4×130.75π×0.062)−1][2513−25] X=0.0398=3.98 % Percentage of muscle =100−3.98=96.02 % Fractions are: 96.02 % and 3.98 % Comment in case any doubt please rate my answer.....

Answered: "Its" - Plainmath

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kramtus51

Answered question

2022-01-04

Its

Answer & Explanation

Joseph Lewis

Beginner2022-01-05Added 43 answers

Total resistance,

\frac{1}{R} = \frac{I}{V}

\frac{I}{V} = \frac{1}{R m} + \frac{1}{R f}

\frac{I}{V} = (\frac{A x}{p f L}) + (\frac{A (1 - x)}{p m L})

x = (((I l \frac{p}{V} A)) - 1) ((p \frac{f}{p m - p f})

X = [(0.0016 \times 0.4 \times \frac{13}{0.75} π \times {0.06}^{2}) - 1] [\frac{25}{13 - 25}]

X = 0.0398 = 3.98

%
Percentage of muscle

= 100 - 3.98 = 96.02

%
Fractions are:

96.02

% and

3.98

%
Comment in case any doubt please rate my answer.....

Medicim6

Beginner2022-01-06Added 33 answers

In the textbook it says the answers are 25/26 fraction of muscle and 1/26 fraction of fat, not sure how they got that though

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