Write each fraction in terms of the LCM of the denominators. 4x−14x(2x+1) 27x3=

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sklicatias

2021-11-12

Write each fraction in terms of the LCM of the denominators.

\frac{4 x - 1}{4 x (2 x + 1)}

\frac{2}{7 x^{3}} =

Charles Clute

Beginner2021-11-13Added 17 answers

Step 1
Given: Write the following fractions in terms of the LCM of the denominators.

\frac{4 x - 1}{4 x (2 x + 1)}

\frac{2}{7 x^{3}} =

Step 2
Now the denominators are:

4 x (2 x + 1), 7 x^{3}

LCM of the denominators is:

\frac{4 x (2 x + 1) \times 7 x^{3}}{x} = (8 x + 4) \times 7 x^{3} = 56 x^{4} + 28 x^{3}

Step 3
So now rewriting the given expression in term of LCM of denominators:

\frac{(4 x - 1) \times 7 x^{2}}{56 x^{4} + 28 x^{3}}, \frac{2 \times (8 x + 4)}{56 x^{4} + 28 x^{3}}

\frac{28 x^{3} - 7 x^{2}}{56 x^{4} + 28 x^{3}}, \frac{16 x + 8}{56 x^{4} + 28 x^{3}}

Step 4
Answer: The expression in term of LCM of denominators is:

\frac{4 x - 1}{4 x (2 x + 1)}, \frac{2}{7 x^{3}} = \frac{28 x^{3} - 7 x^{2}}{56 x^{4} + 28 x^{3}}, \frac{16 x + 8}{56 x^{4} + 28 x^{3}}

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