Bergen

2021-02-12

Two independent measurements are made of the lifetime of a charmed strange meson. Each measurement has a standard deviation of $7\times {10}^{-15}$ seconds. The lifetime of the meson is estimated by averaging the two measurements.

What is the standard deviation of this estimate ?

What is the standard deviation of this estimate ?

Jaylen Fountain

Skilled2021-02-13Added 169 answers

Step 1

It is given that the population standard deviation is$7\times {10}^{-15}$ .

The lifetime of the meson is estimated by averaging the two measurements.

The standard deviation of the two measurements is obtained by dividing the population standard deviation by square$\sqrt[2]{}$ .

Step 2

Thus, the standard deviation of the estimate is,$SD=\frac{7\times {10}^{-15}}{\sqrt{2}}=4.9497\times {10}^{-15}$ .

It is given that the population standard deviation is

The lifetime of the meson is estimated by averaging the two measurements.

The standard deviation of the two measurements is obtained by dividing the population standard deviation by square

Step 2

Thus, the standard deviation of the estimate is,

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