If evan has 10 dimes and quarters in his pocket,

p3sa1bynn

p3sa1bynn

Answered question

2022-04-23

If evan has 10 dimes and quarters in his pocket, and they have combined value of 190 cents, how many of each coin does he have?

Answer & Explanation

Kendrick Fritz

Kendrick Fritz

Beginner2022-04-24Added 12 answers

Step 1
To solve this problem in two variables (dimes and quarters) it is necessary to write two equations.
The first equation is dimes + quarters =10
The second equation is 0.10× dimes +0.25x quarters =$1.90
Now it is clear then dimes =10 quarters so this value can be put into the second equation giving
0.10×(10quarters)+0.25×quarters=$1.90
$1.90=190 cents.
This gives
100 cent10 quarters+25 quarters=190 cents
Now 25 quarters+10 quarters=15 quarters
so 15 quarters+100 cents=190 cents
now subtract 100 cents from both sides
15 quarters+100 cents100 cents=190 cents100 cents
Giving 15 quarters=90 cents. It takes 6 quarters
If there are 6 quarters there must be only 4 dimes
6+4=10
90 cents=0.90
(0.900.15)×(100100)=9015=6
6 quarters×$0.25quarter=$1.50
4 dimes×$0.10dime=$0.40
Total =$1.90

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