Relating an expression to two similar ones Is it possible to express C solely in terms of A and B,

Emery Boone

Emery Boone

Answered question

2022-05-21

Relating an expression to two similar ones
Is it possible to express C solely in terms of A and B, where
A = m x + z , B = n y + z , C = m + n x + y + z
and m , n , x , y , z > 0   ?
If not, how close can I get?

Answer & Explanation

Cordell Crosby

Cordell Crosby

Beginner2022-05-22Added 11 answers

Here is a proof by counterexample that you cannot express C solely in terms of A and B:
Let's take a = 1 6 and B = 1 8 and get these values in two ways:
m = n = 1 ( x , y , z ) = ( 1 , 5 , 3 )
and
m = 1 n = 8 7 ( x , y , z ) = ( 2 , 4 , 3 )
Then using m , n , x , y , z we get C = 5 21 . There are two different values of C for identical values of A and B.
Let's phrase your second question more precisely:
Let
C max ( A , B ) max m , n , x , y , z m + n x + y + z : ( m x + z = A ) $ ( n y + z = B )
and
C max ( A , B ) min m , n , x , y , z m + n x + y + z : ( m x + z = A ) $ ( n y + z = B )
Find C max ( A , B ) C min ( A , B ) as a function of A and B.
Unfortunately, you can't get close at all to the value of C in terms of A and B because for fixed A and B (unless A=B=0),
C = A + ( B A ) y x + y + z + B z x + y + z
so choosing
x = 1 ( k 1 ) ϵ y = 1 2 + ϵ z = 1 2 + k ϵ
and selecting m,n to give the correct values of A,B,both ( B A ) y x + y + z and B z x + y + z blow up as ϵ goes to zero, if the corresponding numerator is non-zero. For any particular values of (A,B) other than (0,0), we can choose k such that those two terms are not negatives of one another. So we can make

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