How to solve advanced fraction problem with algebraGood evening guys, ok so ive been stumped on this for some time and am a bit rusty with my fractions so i was wondering if i could get some help on answering thisI have to try and write this fraction on its own and in its most basic form (simple)The problem: ( a 3 − 3 a 2 8 a 2 − 4 a ) ( a 2 − 9 2 a 2 + 5 a − 3 ) Am really stuck, any help would be appreciated!

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How to solve advanced fraction problem with algebraGood evening guys, ok so ive been stumped on this for some time and am a bit rusty with my fractions so i was wondering if i could get some help on answering thisI have to try and write this fraction on its own and in its most basic form (simple)The problem:                                          (                                                              a              3                        −            3                          a              2                                            8                          a              2                        −            4            a                                                )                                                            (                                                              a              2                        −            9                                2                          a              2                        +            5            a            −            3                                                )                              Am really stuck, any help would be appreciated!

drumette824ed · Accepted Answer

When dividing something by a fraction, we multiply by the reciprocal of the fraction. So we have:                              a          3                −        3                  a          2                            8                  a          2                −        4        a                                      a          2                −        9                    2                  a          2                +        5        a        −        3              =                    a        3            −      3              a        2                    8              a        2            −      4      a        ×            2              a        2            +      5      −      3                      a        2            −      9      Here it can help to factor out terms early on:                    a        3            −      3              a        2                    8              a        2            −      4      a        ×            2              a        2            +      5      −      3                      a        2            −      9        =                    a        2            (      a      −      3      )              4      a      (      2      a      −      1      )        ×            (      a      +      3      )      (      2      a      −      1      )              (      a      +      3      )      (      a      −      3      )      We can now eliminate some terms that appear in both the numerator and denominator. Simplifying, we get:                    a        2            (      a      −      3      )              4      a      (      2      a      −      1      )        ×            (      a      +      3      )      (      2      a      −      1      )              (      a      +      3      )      (      a      −      3      )        =      a    4

How to solve advanced fraction problem with algebra Good evening guys, ok so ive been stumped on t

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