Assume that X is uniformly distributed on (0, 1) and that the conditional distribution of Y given X=

Manteo2h

Manteo2h

Answered question

2022-06-22

Assume that X is uniformly distributed on (0, 1) and that the conditional distribution of Y given X=x is a binomial distribution with parameters (n,x). Then we say that Y has a binomial distribution with fixed size n and random probability parameter.
I have to find the marginal distribution of Y. So I have to use that:
P ( Y = y ) = x = y P ( Y = y | X = x ) P ( X = x )
But when we have that X is uniformly distributed I think the sum becomes a integral so we get:
P ( Y = y ) = 0 1 ( n y ) x y ( 1 x ) n y d x
But what to do next? I think maybe take the binomial coefficient out from the integral, but how then using this to find the marginal distribution of Y? Hope anyone can help me? Do I also have to use that Y has a binomial distribution with fixed size n and random probability parameter?

Answer & Explanation

Jaida Sanders

Jaida Sanders

Beginner2022-06-23Added 18 answers

Your integral is correct. One can show that
0 1 x y ( 1 x ) n y d x = y ! ( n y ) ! ( n + 1 ) ! ,
see the Beta function or order statistics of i.i.d. uniform random variables. Multiplying by ( n y ) = n ! y ! ( n y ) ! and canceling gives a simple expression for P(Y=y).

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