How does this seemingly-trivial simplification work? In a section on inductive proofs in the book M

Grimanijd

Grimanijd

Answered question

2022-07-03

How does this seemingly-trivial simplification work?
In a section on inductive proofs in the book Modelling Computing Systems: Mathematics for Computer Science (Muller, Struth) there is a simplification that is assumed to be trivial, but that I can't figure out.
It occurs in this step:
k ( k + 1 ) ( k + 2 ) 3 + ( k + 1 ) ( k + 2 ) = ? ( k + 1 ) ( k + 2 ) ( k + 3 ) 3
How does one get from the first expression to the second?

Answer & Explanation

wasipewelr

wasipewelr

Beginner2022-07-04Added 11 answers

k ( k + 1 ) ( k + 2 ) 3 + ( k + 1 ) ( k + 2 ) = k ( k + 1 ) ( k + 2 ) + 3 ( k + 1 ) ( k + 2 ) 3 = ( k + 1 ) ( k + 2 ) ( k + 3 ) 3
Riya Hansen

Riya Hansen

Beginner2022-07-05Added 4 answers

Hint:
( k + 1 ) ( k + 2 ) = 3 ( k + 1 ) ( k + 2 ) 3 .
Now combine the fractions and factor out ( k + 1 ) ( k + 2 )

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