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Sam Hardin

Sam Hardin

Answered question

2022-07-09

Let f n : R [ 0 , ) be a sequence of measurable functions that converges to some function f. Suppose that I show that for "n big enough" we have | f n ( x ) | g ( x ) for all x R . Am I right in saying that I can still apply the DCT to conclude that lim n R f n d λ = R f d λ ? I think that I can do this simply because I am removing a finite number of terms from my sequence R f n d λ and then I am applying DCT. Is this right?

Answer & Explanation

iskakanjulc

iskakanjulc

Beginner2022-07-10Added 18 answers

Suppose that | f n ( x ) | g ( x ) for all n N for some N N . Let ( h n ) be a sequence defined as h k = f N + k .
Then in particular h k ( x ) g ( x ) for all k N . Moreover you clearly have that h k f when k .
So you can apply the DCT to ( ( h k )) and you obtain that
lim k R h k = R f .
Now if you go back to the definition of the limit : let ϵ > 0, the above limit implies that there exists K N such that
| R h k R f | < ϵ
for all k K. This implies that
| R f n R f | < ϵ
for all n K + N by definition of h k .
So by definition of the limit, this gives you that
lim n R f n = R f .

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