Determine: | 3 − 2 x | x 2 + 5 ≤ 0

Question

Determine:                     |            3      −      2      x              |                            x        2            +      5        ≤  0

Tamoni5e · Accepted Answer

Step 1Since the denominator   =  (      x    2    )  +  5  ≥  5we multiply both sides of the inequality by the denominator gives,      |    3  −  2  x      |    ≤  0  (  3  −  2  x  )  ≤  0     or     (  3  −  2  x  )  ≥  0    3  ≤  2  x     or     3  ≥  2  x    x  ≥      3    2       or     x  ≤      3    2  therefore,the solution of x is real set = R.

chivistaelmore · Accepted Answer

Step 1The expression   (      x    2    +  5  )  ≥  5 for any value of x.      |    3  −  2  x      |   can not be less than zeroso the only solution is when the equality holds, i.e , when       |    3  −  2  x      |    =  0  ≥  x  =  1.5

Determine: (|3-2x|)/(x^2+5)le 0

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